In this post we will construct the figure of the last post. I will leave the proof open. But i will post it if i get asked.

Problem:

Let a square abcd be given. A semicircle k in the square with the diameter ab is given. Construct a circle in the square, which touches k , cb and dc.

Solution:

First we construct the line through a and c. We extend the side cb to a point e so that cb=be. Then we construct the tangent line to the semicircle k. Let the point on which the tangent line touches k be denoted as x. We construct a perpendicular line to the tangent line through x. The point where this line crosses the line ac ,we denote as n.

Then n is the center of the circle and nx is the radius of the circle we were searching for.